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I toa n, t a gia s u g ia th iet (dieu �i�n) n ao d 6 kh6 ng. hay khong c6 tron g dieu ki�n da ch o cua ba i toa n . Bva vao gia th i et d6 CLing voi n h un g dieu ki�n da cho cua bai toa n de de dang tl m ra each giai cua ba i toa n . Day Ia g ia thiet c6 y n ghia t� m thai v a dap s 6 bai toan kh 6ng ph� t hu¢c vao g i a thiet d6. VI d � 1 : Q uyt n g on moi qua c hia ba Ca m n g o n moi qua chia ra l a m mvoi M o i n g voi m c)t mh�ng, tra m n g voi C6 1 7 qua kh6ng n h ieu du ch ia H o i co bao n h i eu q ua ca m, bao nhieu q ua q u yt? Bai la m : Gias irtat ca 1 7 q ua deu Ia cam thl c6 s 6phan fa: 1 7 x 70 1 70 (phan) = 56phan dura Ia: 1 70 - 1 00 = 70 (phon) Mol/an thay mgt qua quyt bang m¢t qua cam thi s6phan tang them Ia: 1 o - 3 = 1 (phanJ so qua q uytIa: 10 : 1 = 1 o (qua) S6 quii cam Ia: 1 7 - 1 0 = 7 (qua) Dap so : 7 qua cam, 1 o qua quyt Vi d\1 2: Be d�t ong da n n ubc tren m<)t do9n auO'ng c6 the dung 70 o n g dai h o�c 1 20 6 n g ngan N h lin g do d u n g ca h a i l o�i n e n d u n g h et tat ca 90 o n g . Tfn h so ong . m o i IOS� i. Mot. 6ng do; lap duoc:. 1 : 70 -1 (doan auetng). = 7 0 Mot ong. ngan lap dude: 1 : 7. 20 -1- (aoan au'Cing). = 1 20 Arc h i m edes SchoolAschool.edu_vn I 3
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ARCH I MEDES SCHOOL Toa n s - Quyen 4.1 Gia su 90 ong deu la logidai. Biti 1 0. B�n Blnh chia 79 vi<�n bi tha nh 1 2 nh6m sao cho moi n h6m Khi a6 sophan aoan au'ong lap au'dc la: 90 -1 � (aoan au'ong) c6 s6 bi khac n ha u . Hoi nh6m c6 so bi n hiE�u n hat c6 bao n h ieu vien? - . X = 70 7 . � Bai 1 1. B�n An ch�y qua n h , m9t san v�n d¢n g hl.n h c h t1 n h�t c6 £Joan auong dtira Ia: 9 - 1 .� (ao;n aLiang) = ch ieu r¢ng Ia SOm; c h ieu dai Ia 7 1 ,sm va h a i n U'a hlnh tron nhv hl r:th . ' 7 7 . m¢t ve. Biet ding An ch�y lien tl:JC tu 7 g io 30 phut den 8 g io voi v� n toe Moi Jan thay m(Jt 6ng ngan bang 6ng dai, OOt;In attong tang them Ia: tru ng bln h 217km/gia. Hoi b9 n ay di duqc n h ieu n hat b�o nhieu -1 -_l_ 1 (aoQn auong) von g trQn 70 = --. v�n ? 1 20 1 68 "' "" · ..t , � 2 1 r' S o ong ngan a: - : - = 4B tong) 7 1 68 56 6ng daila: 90 - 48 = 42 (ong) £Jap so:42 6ng dai, 48 6ng ngan 7 1 11. BAI T�P Bai 1. Gia dl n h Lan n u oi tat ca 1 2 co n vua g a vua tho. So ga va tho d6 c 6 tat ca 32 chan . Hoi gia d1n h La n n u o i bao nhh�u co n ga, baa n h ieu co n tho? I I. Tf! lu�n Bai 1 2. Cho hlnh bin h h a n h ABCD. E la m<}t diem tren AB. N6i E voi C va B vai D. GQi diem g iao n ha u g i va E C va BD Ia F . Di$n tfch tam giac EFB Ia 2 0 c m 2 va B FC Ia 5 0c m2. Tfn h di�n tfch hln h b1 nh h a n h · ABCD. Bili 1 3. Gia cua 2 q uyen sachf 6 quyen v& va 5 cai but I a 1 54 000 dong . Gia cua 1 0 q uyen sach, 6 quyen vdl 1 0 ca i but Ia 3 74 000 don g . So sa n h g ia 1 q uyen vd vai gia 1 q uyen sac h . Bai 2. Trong rn Qt dc;rt tha m _gia tet tro n g cay. B i et rang moi b9 n nam trong duqc Bai 1 4.Thay p h l) trach c h 9 n cac b9 n I Cip de tham gia cac a¢i, k lap tham gia d<}i S A 5 cay, moi b � n nu t r6ng duqc 4 cay. Lop SA c6 3 0 b9n trong duqc tat ca 1 34 cay. Hoi l op SA co bao nhieu b9 n n a m, bao n h ie u b<:tn n u? trong, _!_ so con i a i tha m g ia doi ken, _l so con lai sau hai lvot tham g ia a6i ca. 56 con 3 . . 3 . . . . l9i tha m g i a dqi diE?u hanh. a) Sap xep cac d¢i thu tlj g_iam dan cua so h QC sinh. b) Gia su 16'p SA c6 54 h9c s i n h. Thay m uon chqn ra l b�n d(?i co, 2 b�n d9i ken va 2 b9 n dc)i trong. C6 bao nhiE�u each thQn? o n eself Sc 1 77 Rise a bove Arch i m edes h oo l and g rasp the world Aschool.ed u .vn. .
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x e o 6 8 xe i �- �,--ilm56_r1h.6 nh at co ba chv so c h i a het ch o 5 m a ton g chu try n g . Tinh xe lo �i. r\ soba n g 1 0. --------:------------------- ---- ··· ··- -·· ··-�·-·· ··-··· ·· : · · ·· · · · ·· -· - · · � . Cho p h im sO HOi p h 3 i them v.'10 tU sO va m a u sO bao iI Gem vi ae dliQ'C p a sO bi\ s6 % . n h i e u h n ng p hil n I 3. day so: 2; 2 2; 222; Hoi so h a d LJ 1 B il i C h o . . . t u 2 1 cua d a y chi 9 l may? I � · - · · - - · - . . · · - · Bili 4. H i�n n ay, tuOi m� giip 4 1 a n t u Oi con. 5 a m n lla , tu6i m� g.3p 3 1a n tuoi con . Tin h tuoi con h i � n n ay. Bai C6 470 b9 n h 9c s i n h tnJO'ng tieu h Qc di tha m q u a n ba n g 6 to. C6 1 2 c hh�c xe 6 t6 gom hai l o9 i : fo9 i xe 3 5 cho n goi va l o 9 i x e 45 cho n g o i (khong ke lai xe) . Hoi c6 Ba i 5.. Tfn h d i$ n tich hl n h sa u : t xe \1 bao nhi?u xe m o i l o � l ? (Mo i cho vl:ra du so n g uO'i) Ba i 6.. Biet d i¢ n t k h hl n h tam g ia c to d$ m I a 2cm2• Tfn h di�n tfch hlnh vu6ng l6'n. Biti Lop SA c6 32 h 9 c s i n h . Tro n g ba i thl m 6 n toa n cu6i na m, ca lop de u dli<;tc 9 ho�c 1 0 di en1 . Bh�t to n g so diem cua ca lop I a 3 1 0 diem. H o i co b a o n h ieu b9 n auqc 1 B a i 7 . B i et a236b chia het c h o 2; 3; 5. Tin h tong ca c c h O' so a c6 the diem 9, n h ieu diem 1 bao b 9 n dut�c O ? viet duqc. f----------------·----···-·············-----------+---------1 Bfd 8. M<?t ch iec ca n o c h �y tn?n kh uc song tu· ben A den ben B . Kh i di xuo i d o ng thl m at 2 g iO'. Kh i di n g uqc dong thl mat 4 g i ct B i et ra n g , n t16'c c h ay v6'i v� n toe 4km/g i0'. H ay tfn h khoang each A B . �-------------------------·------ ----------- C6 8 hlnh l� p p h uong n h o xep thanh tn ¢t hl n h l�p p h uong 16n . Hl n h l ? p p h vong l on dvqc Sdn cac m�t mau do. H o i m o i hl n h l�p p h uo n g n ho duqc son bao n h ieu m at? a n d g raspR i se a bove oneselft h e world Arch i m edesAsc hoo l .ed u .vnS ch ool I 5
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ARCH IMEDES SCHOOL Toa n s - Quyen 4. 1 Bai 6. C6 22 quye n sach Th�n.g Vi�t va Toa n . Sach Tieng Vi�t c6 1 32 tra ng, sach ae THI VAO 6 TRlfcJNG CHU VAN AN (20 1 S - 201 9) Toa n c6 1 50 t ra ng. Tong so tra n g ca hai lo�i s ach I a 3 1 20 tra n g . Hoi moi lo9i sach Biti 1 . b iE�u thuc sau: Tfnh g ia tri c6 bao n h i e u q uyen? . ) A - a - b 1 = 2 X a + 1 9 2 X b khi = 1 000 2) B 2145 X 46 + 8 X 0,75 + 54 X 2,45 + 0,5 X 8 = Bai 2. 1 ) Tu ba chu so 4; 6; 8 hay bi_et s6 t� nhien Ion nhat c6 ba chu so khac n ha u, s6 tl! nh ien be n h at c6 ba chu so khac nhau roi tfnh hi�u cua hai so vua tl m duqc. 2·. ) H - · · so a n' �· 1 25 204 2345 1 25 ay sap./. xep cac p· h "a n "' s u theo thutlj t 'u b 'e d en dn:r ; ; ; . . "' 1 · r - - -- - . 234 2 1 9 2345 21 9 Bai 3. Bai De d�t o n n uoc re m¢t do9n dllong co the d u ng 5 0 o ng d21i ho�c 1 ) Tim so tV n h ien y de bieu thuc: A = 2 1 8 (2 x y 8) c6 g ia trj 16"n n hat. Gia tr� 7 .. g da n t n lon - - 80 on ngan. ca eta 62 Tfnh so n hat cua A I a bao nhieu? g Do d�t hai loe;1i 6ng neri d u n g ong. ong moi lo�i. 2) Cho m¢t so tV nh ien c6 bon ch u so chia het cho ca 2 va 5. Neu b6 chu so hang don v! thl duqc m 9t so c6 ba chu so, so nay be hdn s6 da cho 1 638 ddn v!. llm so aa c ho. 1 1 3 .3) Ti1m x, b• n'tte : X = - + - + - -1 0 2 5 1 0 Bai 4. Cho tam g iac ABC vu6ng t9i A c6 ba c0nh AB 6cm; AC = Bern va BC 1 0c m . = = V e chieu c a o AH tudin h A den c9 nh aay BC. a ) Tin h chieu cao AH. 8.. b) Tre n c;;t n h BC lay diem E sao cho B E = 2 x EC. Tln h di$n tfch ta m g ia c AEC. Bai M ¢t b a i kiem tra c6 15 cau hoi trac n g h i � m . Moi cau tra loi du n g duqc 5 diem, moi ca u tra loi sa i ho�c khon g trii l ai bf tn1 3 diem . M¢t bq n duqc 43 diem. Hoi bqn ay tra loi du ng OUQC bao n h ieu ca u ? Rise a bove oneself Arc h i m· ed es School I 75 and g rasp the world Aschool.edu.vn .
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chi ghi so va o ph an g i ay k h o n g du'Q'C diem n ao. B i et ra n g tong s o di em nam d<)i duqc I a 2 9 diem. c6 : 1 8 X 7 2 + 1 7 X 28 n h ieu tr� n ph a n bi�t thfmg - th u a ? Ca u 2. Boi: 45 km/g io = . . . . . met/g iay Ca u 3 . Tfnh ton g cac so tV nhien l i e n ti ep t v 4 den 20. Ca u 4. C6 bao n h ieu so c6 ba chu. so khac nhau co ton g cac chu s6 Ia 2o? Ca u 5. Ch o hlnh v e ben biet S, = l 2cm2• Tfnh S2. n . T'! lu�n: H9c s i n h tr1 n h bay vao g iay t h i ! Bai 1 0. An th a m gia dau ca va eta aau 20 va n kho n g c6 va n hoa Moi v a n than g duqc . B i d 1 . Hi�n nay, tong so tuoi c u a ba n g uoi m ¢ t g i a di n h I a 8 3·. Biet b 6 han con 2 7 1 0 diem, moi va n b! mat diem Sa u 20 daul A n 5 0 t h u a 5 . va n duqc dit�m . Hoi A n da tuoi, m � h a n con 2 3 tuoi. Tfn h tuoi c u a moi n g lioi. Bai .2. Tr ng A rc h i m'edes EJ 6 n g A n h d i m h 60% sO phO n g lam p h O ng h qc, ± sO tha n g bao nhieu van ? UO p ho n g lam p hong ch uc n a ng va 1 8 p hong con l�i danh cho vi�c v�n h a n h . Tinh so p h ong h9c? Bai t ang 4 c6 1 1 90 so hQc sinh tha m B iet rang % nu f)Qt Every Ste p h g i a . s6 b9n ban g �s 6 b� n na m . Tfn h so h c s i n h n ul s o h qc s i n h n a m tha m g i a . q Bai 4.. N g uoi t a xep cac khoi l�p p h uO'ng n h6 gi6ng nhau th� nh m ¢t hrn h f� p p h uang 1 6'n sa u d6 san 4 m�t xu n g q ua n h ba n g m a u do va son m�t tre n c u n g ma u xan h . Biet ra n g c 6 1 6 khoi nho c h i avqc son duy n hat m a u xa n h . Tln h s o kho i l � p p hU'ong n ho b a n dau, tfn h s o kh6i chi du'qc son d u y nhat m a u do . Bai 5. Luc 6 g io sa ng, m9t xe may cti tu A den B voi v� n toe 30 km/gio. Luc 6 g io 30 p h ut, m 9t 6 to di tU' A den B v6'i v� n toe 42,5 km/gi0. 0 to duoi kip xe m ay t�i diem C each B Ia 7km . Tfn h q u a n g duon g AB. a nd g raspRise a bove oneselfthe wo r l d A rc h i m ed es S c h oo lAschool .ed u.vn I
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ARCH IMEDES SCHOOL Toan s - Quyen 4. 1 BAI T�P THAM KHAO £>E VAO 6 TRliONG ARCH IMEDES ACA DEMY (THANG 3 - 20 1 9 - 2020) Bai 1 1 . (Marie Curie 20 1 2 20 1 3) M9t phong hQp xep duqc n h i e u n hat Ia 1 8 b¢ ban I. Trac nghi�m (Hqc sinh chi ca n g h i dap so) � chlqc STT Nc?i dung cau hoi aap so g he. co hai lo9i ban ghe, l o�i th U' nhat ngoi dvqc 4 ng uoi, lo<?i th u h a i n goi .1 Tfn h : 0,25 X 1 70 + 25% X 1 30 5 nguoi. De c6 83 nguoi d tj h9p thl pha i xep bao nhieu b¢ ban g h e moi lo9i? (Cach 2 llm cac chu so a; b biet: 28a74b chia het cho 5 va 9, xep phai dam bao a i cung c6 cho ngoi va kh6 n g co cho nao trong) tong.cQ-a 3 Tlm hai so th� p phan/ bi�t c h u n g I a 25,9 1 va hi�u Ia 22,29. Bid 1 2. M¢t so tie n gom _29 ta vua l o9i 5 000 dong, vua lo�i 1 0 000 dong. So tien lo� i 4 Cho ta m g ia c vai cac ti I� nhu h1 nh. Bif!t 1 0 000 dong nhieu hon so th�n l o9 i 5 000 don g I a 1 25 000 dong Tfn h s o t a moi l o9L 53 - s, 84cm2• Tfn h 54 - S2. . = Bai 1 3. M¢t 16p mua 50 v e xem xiec gam 3 lo� i : lo9i ve 50 000 do n g( lo9i ve 3 0 000 dong va l o9i ve 20 000 dong het tat ca 1 700 000 dong . Biet so ve 20 ooo don g gap d6i so ve 30 000 dong. Hoi c6 bao n hh§u ve moi l o9 i? I Viet s6 16'n n hat c6 7 c h u so khac n h a u va chia het c h o 36. L___s __t___ __ T':t' lu�n: (H9c___ ___.....•..... ·················-········ 1 1 . sinh tr1nh bay bai g i a i). Bai 1 4. Co 1 8 6 t o g 6 m 3 l o9i: lo�ti 4 banh ch6' du'qc 5 tan, lo9i 6 banh ch& du<;ic 6 tan Bai 1 Thu' vien. tru'dng Archimedes c6 � so sach I a sach khoa hoc _!_ so sach Ia sach � 5 . , va I 09 i 8 ba n h c h (J du'CJC 6 tan, 1 8 xe do c h o auqc tat ca 1 0 1 tan h a n g va c6 tat ca 3 van hQCI con l<? i 276 quyen sach ky nan g song. Tfn h so sach khoa h QC, so sach van 1 06 ban h xe. Hoi moi lo�i c6 bao n hi e u xe? hc;>c co trong t h u' vi �n. B f.li 2. S a u 3 b a i kh?m tra,� m¢t lop c6 so b9n auqc 3 di e m 1 o b ang s o b� n duqc 1 Bai 1 5. L6p SA c6 5 to trang cay, so n g u'oi moi to deu b2 mg n h a u . Moi b9 n trong atJQ'c ctiem 1 o va bang so b9n dliQ'c 2 di em 1 o . Tln h so h9c sinh cua l6'p, b i et tong s6 4 h o� cay. Ca lop trong ca 4 cay? diern 1 0 Ia 60 bai va c6 4 b9n c h u·a d�t cHem 1 o. c 6 duQ'c tat 220 cay. Hoi c6 bao n hieu b9n tr6ng dvqc Bai 3.. M¢t lop quyet di n h di a n Pizza bang tien q uy lop. B iet n eu an s uat 30 nghln Baa hieu b� n trong duqc 6 cay? Bh�t so hc;>c sinh hon sol 40. thl thua ra 1 60 nghl n va neu an suat 40 nghln thl c6 4 b9 n kh6 n g duqc an. Hoi 16'p d6 n ft n hi e u hon · n h ieu b9 n c6 bao va q uy 16'p co bao n h i e u tif�n? Bai 4 . M¢t b e bai dai 33m, r<) ng 1 2m va s a u 1 m 80cm. N g lfcri t a dun g g�ch men hl n h vuong c6 c9 n h I a 3 0c m ae I at xu ng qua n h tha n h be va day be. Tln h so 9 9ch d u n g ae lat be boi ao. Bai 5 . C6 tuoi chua 75o/o nu'Cic Phoi 3 t� co tuoi thl duQ'c 1 20 kg co k h o . Tfn h % n uoc . tro n g co kh6. Rise a bovethe worldoneself Arch i m edesAschool.edu.vnSchool I 73 and g ra sp
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1 . u 1 S m th1 di�n mieng oat g l a m 1 70 m2 • Tin h di�n i D I a d i e m c h fn h g i O'a cua ai em M P h uon g ph a p k h u Ia phudn g p h a p du'Q'c d u ng t ro n g cac bai to,an tfn h n h i eu d9 i g ac CC? n h B C . T ren C<? n h l vq n g (2, 3, 41 ... d9 i lvqng). sv dl)ng du ki $ n cua bai toanl nham 11khCt di m 9t so da i sa o c h o AM = 1 AC. luqn gi g i O' l � i m9t d9i l vqng ae tfn h ra ket qua, roi tiep theo Ia tfn h n g vqc l � i cac 3 d9 i l uqng con l9i. a ) S o sa n h di$n tfc h h a i ta m g i a c A D M va ABC g 1 : Co san aqi htqng aa cung h? so b) Tre n c9n h A B lay ctiem N sao ch o A N = N B. Tfn h d i$n tich tam iac DMN, neu H a mua 3 . b u t xanh v a 7 b u t do het 1 34 0 0 0 aong. ·Neu m ua 3 but xan h v a 4 b u t do b i et d i $n t fc h tam g iac ABC I a 640cm2• nh v t h e het 92 000 don g. Tfnh g ia tien 1 but xa n h, 1 but d6 . Tom tat: 3 b u t xa n h + 7 but do = 1 34 n g hl n do n g ( 1) 3 but xa n h + 4 but do = 92 n g hi n ao n g (2) Tfn h g ia tien 1 but xan h, 1 b ut do. B a i l a m : Trif2 ve ( 1) va (2) ta c6: 7 but do h an 4 but ao la: l - 4 = 3 (but) V¢ymua 3 but tld het so tien lri: 1 34 000 - 92 000 = 42 000 (dong) Gia 1 but ao Ja: 42 ooo : 3 = 1 4 ooo raongJ Gia 1 but xanh Ia: ( 1 34 ooo - 1 x 7 4 ooo; : 3 = 1 2 ooo (i16ng) Dap so: But xanh:72 000 dong, but do: 74 000 i16ng Vi d �- 2 : Cdc agi !uqng khdc h� so (Cdch giai fa alia m(>t agi /u(;mg ve' cung h? so r6i lfkhil"). Vy mua 5 q u yen vo va 3 ca i but het 1 1 1 000 dong. San m u a 3 q uyen va va 5 c a i b u t c u n g l o� i het 1 O S 000 don g . Tfn h g ia tien 1 quyen vd, 1 ca l b u t. To m tat: 5 quyen vCi + 3 ca i b u t = 1 1 1 000 dong ( 7) 3 q uyen vo + 5 cc H b u t = 1 OS 000 dong (2} Tfnh g i a th � n 1 quye n vo, 1 ca i b ut. Rise a bove o neself Arch i m edes Sc ho ol and g ra s p the wo r l d Asch o o l .ed u.vn
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ARCHIMEDES SCHOOL Toan 5 - Quyen 4. 1 DETHI VAo 6 TRUONG f>OAN THI £>IEM (201 9-2020) 1. Phan trac nghi�m Tf{(1) ta co: 15 quyen va+ 9 cdi but = 1 1 1 000dong X 3 = 333 000 dong Cau 1 . Tong cua 9 so tlj nhh�n l i e n t iep tu 1 aen 9 c6 ket qua I a : Tfl (2) ta co: 15 quyen va+ 25 ccii but = 1 05 000 dong X 5 = 525 000 aong A. 45 8. 50 C. 5 5 0. 60 25 cai but nhieu han but Ia: 25 - 9 {cai but) cau 2. s o s2 gap bao n hieu lan s o 0,875? 9 cdi = 7 6 4 Gia tien 1 6 cdi but a6 Ia: 525 000 - 333 000 = 1 92 000 (dong) A. 4 8. 6 C. 1 4 0. 2 1 Cau 3 . ChQn so t h fch hqp vao c h o tr6ng, bh�t : 1 8,987 = 1 8 + 0,9 + . + 0,007 . . Gia tien 1 cai but Ia: 1 92 000 : 1 6 = 1 2 000 (dong) A. 8 B . 0,8 C. OrOB D. 01008 Cau 4. So nao duoi day th u9c day tinh: 1 ; 3 ; 4 ; 7 ; 1 1 ; 1 8 ; Gid tie'n 3 cdi but Ia: 12 000 X 3 = 36 000 (dong) . • . . . . A. 30 B. 40 C. 45 D. 47 Gia tien 5 quyen vi'J Ia: 1 1 1 000 - 36 000 = 75 OOO.(a6ng) Cau 5 . Hln h thang ABCD c6 day C D g ap q6i day AB va d i$n tfch ta m g iac ABO Ia tien 30cm2• Di$n tich cua hl n h thang ABCD Ia: Gia 1 quyen v& Ia: 75 ooo : s = 1 5 ooo (dong) A. 80cm2 B. 90cm2 C. J 00cm2 D. 1 20cm 2 f)dp so: 1 eel;but: 1 2 000 dong; 1 quyen va: 1 5 000 dong. Cau 6 . N e u b a n kfn h m9t hlnh t ron tan g them 20% thl d i� n tfch hlnh tron ta n g them d �;� 5 6,54cm2• Di�n tfch cua h1nh tro n d6 Ia: Vi 3: Mua 3 kg q uyt va S kg cam het 370 000 a6ng. Biet g i a tien 2kg qu)ft hon g ia A. 1 28,5crn2 B. 67,848cm2 C. 1 1 3,08cm2 tit�n 3 kg cam I a 25 000 dong Tfn h gia tien 1 ki-lo-ga m quy-t, 1 ki-lo-ga m ca m . Phantt! lu�n . 11. Tom tat: Ba i 1 . Tfn h n h a n h: 4 7 27 4 7 b) S x 7 x 9 x 1 1 x 1 3 x 1 5 q uyt + Skg ca m = 3 70 ooo (1 ) a} 3 + - x - x - x 3 - - - 3kg don g 9 25 1 2 7 25 3 0 x 26 x 22 x 1 8 x 1 4 x 1 0 2kg q u)ft - = 25 (2) Bai 2. 3 kg cam ooo don g 1 . Ti m x, biE�t: (6,27 1 ,38) : (x : 2) 3,26 - = _ Tfn h g i a tien 1 ki-lo-ga m q uyt, 1 ki-16-g a m ca m. 2. Tre n ba n Ia 3 cuon sach g iao khoa : Va n, Toa n va Tieng A n h duqc bQc 3 mau kh ac nha u : Xanh, do, va ng. Chci biet cuon bQC b1 a mau do a�t giCta 2 cuon Van va Tieng A n h, cuon Th �n g An h va cu6n mau xanh mua cung 1 ng ay. B9 n hay xac ai n h moi Tit(1) ta c6: 6kg quyt + 1 Okg cam = 370 000 a6ng x 2 740 ooo dong = . CUOn sach da bQC b)a mau gJ? Til(2) ta c6: 6kg quyt -- 9kg cam = 25 000 oong X 3 75 000 dong. Bai 3 . = 1 . Ti m m<?t so h! n hien A c 6 2 cha so, biet rang n e u viet ch iT s o 0 xen g i ua c h O' so Neu thay6kg quytbang 9kg cam th1 1 9kg cam c6 so tien Ia: h a ng c h l)c va h a n g de1n vj cua so A ta dti<;:tc so B Ian gap 1 0 lan so A, neu viet them 740 ooo - 1s ooo = 665 ooo (aongJ chu so 1 vao be n trai so 8 thl ta duqc so C I an gap 3 l a n s6 B. 1 kgcam c6 gia Ia: 665 ooo : 1 9 = 35 ooo (oong) chia 2. ll m so tu nhien a nho nhat sao cho a chia cho 2 dv 1, cho 5 d u 1 1 chia cho 7 Skg c6 gid Ia:35000 x 5 = 1 75 000 (dong) d l1 3 va c h ia het c h o 9. 3kg quytc6 gia Ia: 370 000 - 775 000 = 1 95 000 (dong) M(>t etta h a ng ra li qua c6 ro aljng ban het � so va Bai 4. 2 ca m va b lfdi. Sau kh l ca m 1kg quytc6 gia Ia: 1 95 ooo : 3 = 65 ooo (dong) : so buoi, n g lioi ban hang t h ay ra ng ca h a i lo�i con l�i 1 65 qua, trong d6: so blioi Ddp so: 1kg qujt: 65 ooo dong; 1kg cam: 35 ooo dong bang � so c:a m . H o i luc dau cua hang a6 c6 bao n h ieu q u a moi lo9 i? Rise a bove oneself Arch imedes School I 7 1 a n d g rasp the world Asc h ooLed u.vn · .
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2 cao cao 2 1 tln h b o tui, 1 ch i ec L3 bao n h i e u ? 0,007 tam g iac c6 a¢ dai c h i e u cao ba n g 6cm Ia: Tom B. 30cm2 D . 60cm2 TI so p h a n t ra m cua 3 5 va 8 I a : 2 m ay tinh 3 vf = 23 8 ooo dong { 1 ) - A. 4,375o/o B. 43,75% C. 437,5% D . 43 75% 30 Qua ng avong tu Ha N9i aen Ha i Phong d a i 1 1 s k m . M9t 6 to khO'i h a n h tu Ha 3 m ay tfnh - 2 v f = 8 5 7 000 don g (2) .. NQi luc 6 gio 6 p h utr den Hai P h6ng l u c 8 gio 24 phut. V� n toe c u a o to I a : Tfn h g i a 1 may tln h, 1 vL A. 40km/h B. 48km/h C. SOkm/h D. 54km/h 3 1 . Lam 48 l9 m ltt ca n 18kg trai cay. Hoi m u on lam 1 6 IQ mat n h li the ca n bao nhieu ki-lo-g am tra i cay? A. 6kg B. 3 kg C. 1 2kg D. 8kg Tu (1) tac6: 4 may tinh - 6 vi = 238 ooo x 2 = 476 ooo (dong) Ciu Ton g cua b a so ba ng 22,9. Tong cua so t h v nhat va s6 th u h a i bang 1 3,7. Tu (2) ta c6: 9 may tfnh - 6 vi = 857 ooo x 3 = 2 57 1 ooo (dong) Tong cua so t h u n hat va so thu ba ban g 1 7. So t h u n h at I a: A. 5,9 B . 7,8 C. 8,7 D. 9,2 V¢y9 - 4 = 5 m ay tfnh c6 gia: 2 57 1 000 - 476 000 = 2 095 000 (dong) Ciu 33 M 9t ola hang b a n chi ec may g i�t duqc 3 3 00 000 do ng, t f n h ra eva hang da .. lai 25o/o gia von. Gia von cua c h h�c m a y gi�t a6 I a : 7 chiec may tfnh c6 gia la: 2 095 000 : 5 = 4 7 9 000 (dong) A . 2 475 000 d B. 2 640 000 d C. 2 825 000 d D. 4 1 25 000 d 2 chiec may tfnh c6 gia Ia: 4 7 9 000 X 2 = 838 000 (dong) Cau 34. M 9t bon hoa hl n h tron c6 d i $ n tfch 1 53/86dm2. Tfnh b a n kfn h bon hoa. A. 7d m B. 7 5dm C. 49dm D. 1 08dm 3 ch iec vf c6 gia Ia: 838 000 - 238 000 = 600 000 (dong) , Cau 3 5.. Ti m d¢ da i m a. SOo/o cua n6 Ia 80c m . A. 40cm B. 1 ,2m C. 1 ,6m D. 60cm 7 chiec vi c6 gia Ia: 600 000 : 3 = 200 000 (dong) 36 M Qt kh 6i go hln h l� p ph uang c6 c9 n h d a i 0 4m Biet 1 d m3 go ca n n � n g .. , . so: chiec 0,65kg. Khoi go do n�n Bop 1 may trnh: 4 1 9 000 dong; 1 chie'c vf: 200 000 a6ng ca n g Ia: A. 41 6 kg · B. 4 1 /6kg c. 1 04kg D. 1 0Akg cau 37. 63 g i o = . . . tua n Phan so thfch h qp dien vao cho c h a m I a : It B AI T�P A. ]_ B. � C. � D . � Bai 1 6.. Mua 3 g 990 te S g g�o nep het tat ca 1 45 0 00 dong. M u a 3kg 990 te va k va k 3 4 8 8 Cau 38. M ¢t ma n h dat hl n h thang c6 d i �n tkh 32m2, chieu cao ban g 4m, day lon 7kg g 9 o nep h et tat ca 1 85 000 ao n g . Tfn h g i a tien cua 1 ki-16-ga m 990 moi l o�i. hdn day be 6m. DQ dai day Ion cua hl n h thang d6 Ia: A. 5 m 2 B . S m C . 6 m D. 1 1 m Cau 39. M 9t vuon hoa hlnh ch u n h�t c6 ch u vi 1 1 2m . Chieu rqn g bang � chieu dai. 5 C h i e u dai vuon hoa d6 Ia: A. 70m B . 35m C. 2 1 m D. 671 2 m C h u vi hl n h chu n hat. c6 c h i e u d a i � m va d l en t fch 25 m2 � a : 3 . 1 2 3 5 5- m5 C. � m A. -- m B. 1 2 6 3 5 Rise a bove o neself a n d g ra s p t h e world
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ARC H I MEDES SCHOOL Toan s - Quyen 4.1 Bai 1 7 Ng uai thu nhat m ua 3m va i hoa va Sm vai I!:I a· het 500 000 dong. �guCii th u Cau 1 2. Di� n tlch toan phan cua hl n h t � p p h lidng c6 c9nh dai 4,5 m I a: . . h a i m ua 4m va i hoa va S m vai 1 �a cung lo�i het 550 000 dong. Tfn h g i a th�n 1 m vai 2 C. '1 m A. 1 5 m B. 8- 1 m2 D 9 1 25 2 a 1 m vai ll)a. 1 2 1 ,5m2 • · h o , Cau 1 3. Tkh : 2020 � 0�001 hon so nao d u&i day? l on A. 2,0 1 9 8. 2, 1 9 C. 20, 1 9 0. 20 1 19 Cau 1 4. M9t voi nvac trong 2 gio 45 phut chay du'Q'c 3 m3 n u'oc vao be. Thdi g ia n de voi nude c h ay auqc soo/ n uoc Ia: c. 2 7 p h ut 3o A. 27 phut 5 g iay B. OA5 gia D . o,3s gia g iay Cau 1 5. 3,5/ da u hoa n � ng 2,485 kg . Hoi c6 bao nhieu lit d a u h 6a neu khoi l uc:;;ng cua · chung Ia 5,68kg? A. 7/ B . 7,5/ (. 8/ D. 8,51 cau 1 6.. Tim x� b i et: x x 6,28 = 21 ,98 A. 3,4 B. 4 (. 4,5 Cau 1 7.. S kg 3 g = . . . Bai 1 8. Van p h ong n h a truong l a n aau m u a 2 4 chiec but may va 1 2 chiec but chi het Ket q u a du n g di e n vao cho cham Ia: tat ca 876 ooo dong. U3 n sau mua 12 ch h�c but may va 8 chiec but chi cli ng lo9i het C. B. 503g D. 5 3 00g g ia tien moi ch e but tu 1o9i. � 5,0003kg tat ca 444 000 don g . Hay tfn h i c ng Cau 1 8. M¢t n g uoi di xe may trong p h ut dttqc 3 24m. Hoi tro n g m (?t g iay n g voi d6 Oi du'<JC bao n h ieu met? A. 27nl B . 1 2m C. 3888m 5. 270m Cau 19. Ta u Thong Nhat xuat phat tu Ha N<)i l uc 21 g ia 3 0 phut n gay 30 thang 5 nam 201 9 den thanh pho H 6 Ch i Minh l u c 4 g id 30 p h ut n gay 1 thang 6 nam 20 1 9. Thai gian ta u Thong N hat ai tu H a N9i den Thanh p h o H6 Ch f M i n h Ia: c . 3 0 . g i o 3 o A. 29 g ia B . 30 g i a D. 3 1 gio p h ut Cau 20. 3_i_ = . . . 50 56 th�p pha n thfch h qp ctien vao cho c h am Ia: A. 3145 B. 3,450 C. 3�8 D. 3,08 Bai 1 9. Hai Nam mua q uye vd va but het 35 dong. Doan Sctn q uyen Cau 21 Trung bl n h c<) ng cua ba so tv n h ie n l ien tiep Ia 3. B6 I a ba so nao? 2 n 3 cai 000 m ua 3 . . 4 A. 1 ; 2; 3 B . 2; 3; C. 1 ; 3; 5 D . 0; 3; 6 va va 2 cai but cung lo�i het 40 000 dong. Tfn h gia tien 1 quyen vo, 1 c§l b u t. Cau 22. Chu s6 s6 th�p ph 1 9,768 8 tro n g an t h u () c h a n g : A. don vi tc." Hang phan H a ng B. Hang nghl n D. Ha ng phan nghl n ram Cau 23. Nam 2020 co bao n h i e u thang c6 3 1 n gay? A. s tha n g B . 6 thang c. 7 thang D. s tha n g Cau- 24.The k l XXI c 6 bao n h i e u n a m n h u �n? A. 3 3 na m B . 25 na m c. 75 na m D. s.o n a m Cau 25. M9t ca n o x u 6 i dong t u ben A den ben B het 1 g ia 2 0 ph ut� V� n toe cua ca no khi n uoc yen l � n g Ia 24km/h va v�n toe d o n g n u'6'c Ia 3 km/h. Chieu da i q ua n g s o n g AB I a : A. 20, 2 5 km B. 32,4km C. 28km D. 36krri Rise a bove oneself Arch imedes School I 69 and g rasp th e worl d Aschool.edu._ vn
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A 8 A 20�D, B 5 0, 5 1 0°/o h a i p h a n xuO'ng l a m auqc 1 0 1 5 b Q q u a n ao. Hoi- tua n m o i 4,6m = . . . e m xuan g 1 2nn b a o n h i e u b ¢ q uan ao? ' 5 6 t h ic h h qp ctien vao c ho cham Ia: 460 8. 406 (. 4600 D. 4060 cua 3 1 1 ,a:, G i a trj bie� u t h uc: 2 - X - X 1 -2 I 5 4 A. ]_ 3 9 C. 2 ]_ 1 B . 40 D. 1 -40 40 40 An h Q c ba i tv 8 g iO' 1 5 phut sa n g . An l a m bai t� p h et 1 gio 1 0 p h ut ro i nghi giai lao 1 5 p h ut, sau d6 o n t� p l 9 i cac m6n h et 4 0 p hut. V�y _An h<;>c xo n g luc A. 1 0 g i o 20 B. 1 0 g i a 40 c. 9 g i o ss p h ut D. 1 o g i a 1 o p h ut ph ut phut . C a u 5 . n rn so t h ich h qp ctien va o c h o tr6 n g t ro n g bang sau: B�Ji C 6 b a b a a 9 9 0, bao thu n hat v a b a o th v hai ch ua tat c a 99kg, ba o th u h a l va E 1 I 4 I 9 I 1 6 ? bao th u ba c h ua tat ca 96kg, bao t h ti ba va bao th U' n h at c h ua tat ca 93 kg. H o i moi A. 2 5 B . 36 C. 2 9 D . 30 o xung bao chua bao n h h � u ki-16-g a m 9 9 0 ? cau 6 . N eu g a p c9 n h cua hi n h l � p p h uong l en 1 l a n t h l d i� n t fc h q u a n h cLta hln h l�p p h vong do gap l e n so I a n I a : A. 1 o lan B. 40 i a n c. 1 oo 1an D. 1 ooo 1a n Cau 7 . l h chu n h�t c6 dai ba ! chi�u /'Vl<)t san tnton g h n ch i e u 40m , c h iE�u r¢ n g ng dai. N g uoi ta l at sa n tru'ong ba n g cac v i e n g(jlch hl n h vuong c6 Cqn h dai 4d m . H o i ca n dung bao n h ieu vien g�Kh de lat kin s a n truon g ? (Di�n t fc h p h a n m q c h vua k h 6 n g · · aa n g ke) A. 400 v i t� n B . 300 c. 15 ooovien D. 7 5 0 0 v ie n vie n C a u 8 . Q u a ng du'O'ng t lt n h a den truon g d a i 7 5 0m . Tren ban do tl I� 1 : 5 0 000, Bai Ba b9n gap r n Lan va H u� gap duqc nhieu La n, H u� v a H a n g 6 i sao. B i et a g 1 1 6 ngo i qua n g au'ong dai bao n1i - l i -rn et? C . D . sao; La n va Ha g a p avqc 1 25 n g 6 i s a o; H u � va Ha gap dvqc 1 2 1 n g 6i sao. Hoi moi b� n A. 750 m m B . 50 OOO m m 1 5 m m 1 5 0 tn m C a u 9 . P h a n s o chi pha t o mau tro n g hl n h b e n I a: g a p duqc bao nh ieu n g o i sao? n A. � B . � C. � D . 4 4 5 9 9 1 So n a o d u6'i day ch i a h et cho ca 2; 3 ; 5; 9? A. 720 8 . 675 (. 495 0. 750 1 2004 2 005 2006 2007 p a n so nao dn h A'a t . 1 . Tran g cac pF h A.a n so:A' -- ; -- ; -- ; -- , h � ' I F n 7 2005 2 006 2007 2008 _, . 2oos . 2007 A 2 0 04 2005 c_ D 2008 B. 2 0 0 5 2006 2007 R i se a bove o n eselfthe A rch i n1ed e s School I 3 a nd g ra s p wo rl d A s c h o o l.ed u .vn
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ARCH I M EDES SCHOOL Toan s - Quyen if. 1 Bai 23 . Minh muon mua me?� so ba n h ngQt va pizza cho bua sinh nh�t cua mi nh. Biet Ti m so tV n hh�n l&n n hat c6 ba chu so, biet rang so d6 chia 1 6 c 5 chiec ban h ngQt co g i a bang 2 chiec ba nh pizza. M i n h mua 4 chiec banh ng9t va cho 3 d v 2, hia cho 5 -dv4, chia cho 7 du 6. ··�- Hoi c6 ba.o n h ieu each ChQn ra hai so kha c nhau trong cac so 3 chiec pizza het 1 1 04 nghln don g . Tln h gia tien 1 ch iec ba n h ng9t, 1 chiec pizza. 1 7 cua ... t\f n h i en tu 1 den 20 sao cho tich ch u n g chia het cho 9? Cho hlnh l�p ph uong c9 nh bang 6cm du<;c t9o th anh bai G�C hlnh l � p phllong C(;ln h 1 e m . Ngu'O'i ta son cac m �t cua 1 8 hl n h l�p phuong lon, sa u d6 b6 di cac hln h l�p p h uong n ho chi auqc son m(lt m�t. Tfn h di�n tfch toa n p h a n cua hl n h con I 9 L B iet A = 1 x 2 x 3 x... x 1 00 ch ia het cho B = 1 00 . . . 0. H o i B c 6 the 1 9 c6 n h ieu n hat bao n h ieu chu so O? C6tat ca baa n h ieu hl n h vuong trong hlnh ve ben ? · : : . 20 j Bid 24. Biet 5 con tho va 2 con d e n � n g 8 1 ,Skg; T con de n�ng han 1 co n tho 29,2kg . .•. Hoi con tho, con d e bao ki-lo-gam? •• .' m o i moi n � n g n hi eu :,. ·· ··"· Bai 25. M (>t n g uoi mua 3 cai ba n va 5 ca i g h e p h ai tra so t i t? n Ia 2 45 0 000 a6ng. G ia m{>t cai ban dat hdn g ia m(>t ca i g h e Ia 230 000 dong. Hoi g ia m(>t ca i ban, m(>t ca i ghe Ia ba o n h ieu? Rise a bove oneself 1 67 Archi medes School a nd g rasp the world Aschool.edu.vn
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m ua moi ca i g �e gia moi 1 . -3 2 : x - - = 7 620 o o o don g ; h et ca 4 540 000 dong Neu trudng mua so ban du ng ba n g ghe 4 4 . ' , ll m 2 so b i et tru ng bl n h cqn g cua hai so d6 ba n g 75 va hi$u 3 da mua va mua so g he du n g b a n g so ba n da m ua thl p h a i tra n h it�u h an so voi ban cua chung bang 30. Tim cac chu SO X va y sao c h o 2x5y c h i a het cho cac SO 2; 5 4 ct3u· 380 ooo dong. Hoi tnfang mua t h e m bao n h ieu ca i g he, bao nhieu cai ban ? va 9. Tfn h di$n tfch cua m (>t hl n h c h u n h� t c6 ch u vi bang 2 5 2 cm 5 va chh�u d a i B a i MQt cai ao s d m i dat han m ¢t e<§ i a o p h on g 2 1 0 nghln dong. 3 cai ao s o m i va gap d6i c h h ? u r()ng. 6 1 5°/o cu a 90 Ia M9t hln h h¢p chu n h�t c 6 day I a h1 n h vuong c� n h 2 5 c m va 2 G� i ao phong gia 2 3 80 n g hl n don g . Tfnh g ia t i e n 1 ca i ao Sd mi va 1 C<li ao p h o n g . 7 cao cua d6. chh�u bang· 1 ,5d m . Tln h the tfch hl n h h ¢ p 1 m so b ' at trong 1, 00 1; - ;7 2020 ; -8 Bid 2 8 . G ia tie n 4 quyen sach nhieu h.on g ia tien 8 q uyen vo Ia 4 4 0 0 0 dong, g ia t i e n e nh "' cac so s a u :� "' 8 T1 ... . -- 8 20 1 9 9 !-- -+- --:-- - Luc 7---------------- -fa B vai v� n----····-········-····--····· . ············-····-··-·-··-············- ···· · · · ··· ··········-········-·-· q uyen s h 9 va g ia sa ng, mqt nguai xuat phcH tu A di ve p h 1 2 ach n hieu han gia t �n q uyen Ia 2 5 2 0 0 0 don g. Tfn h gia tie n m o i toe 4 0km/h . Sau do 3 0 p h ut, n g uai t h u hai xuat phat t u B, di 9 ve phfa A v6i v� n toe 30km/h . Bh?t q uang duan g AB d a i 1 60km . Hoi hai n g u'ai g�p n ha u luc may gio? ll m p h a n so n ho nhat c6 tong c u a tu so va m a u so bang K c6 so n bi. Bh?t la n b i u 1 0 Bid 29. H a i b�n Quang va han h m¢t vie 4 so c a Q u a n g n h h�u 20 1 9. Vao n gay kha i trudng , m 9t cU'a hang do chdi g ia m g ia m9t l a n so bi hanh va 2 ian so b Kha n h n h ieu hon 3 an bi hon 2 c u a K I a 1 4 v i e n i c u a l so b¢ Leg o 1 0°/o. N gay h o m sau, n h an d ! p q uae te thieu n h i , 1 1 eva hang l9i g i a m the m 1 Oo/o g ia dang b?n n e n g i a ba n I a cua Ia 39 Tfn h so bi cua moi b9n. Qua n g vie n. 405 ooo don g . H o i tnJac khi gia m thl b q Lego c 6 g i a bao n hieu? Cho hl n h ve biet chu vi h1 n h t ro n Jon n h at ban Bai 30. M¢t n g tJO'i mua 3 q ua ca m , 2 qua tao va 5 q ua le h et 538 n g hl n dong. Neu ben , g 1 234cm. Tln h to n g c h u vi ba hl n h tro n con l9 i . mua 6 q ua ca m va 4 q ua tao th1 mat 546 n g hl n do n g . Neu m u a 2 q u a c am, 3 qua tao va 4 q u a l e thl mat 509 n gh1n dong. Tinh gia 1 qua ca m. 1 2 1 3 Ket q ua cua pheph tin h : 9 + 1 9 + 29 + . . . + 2 0 1 9 I a M t? s i n h con vao nam 2 0 1 9 khi m� 2 6 t u oL H o i den n a m n a o 1 4 ba thl tu o i m � gap lan t u o i co n ? f)e aanh s6 tran g m <)t c u on sach (bat da u tlf t ra n g 1 ) n g uai 1 5 ta ca n d u ng 642 chu so. H o i cuon sac h a6 co baa nhit�u tran g? 1 15 R i se a bove o n eself A rc h i medes Sc h oo l and g rasp the wo rld Aschoo l . ed u .v n
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ARCHIM EDES SCHOOL Toan s - Quyen 4. 1 BAI 3 . ON TAP BE THI VA.O LOP 6 TRlfONG NGUYEN TAT THANH (201 9 - 2020) • Bai 1.Phan 1 : Trac nghiem nh?t Bln h thLr I. ON T�P VE TfNH NGli(JC Nam 20 1 9 sin h vao ngay Ba tha n g s. Hoi sang nam sinh n h�t Bf n h vao ngay th u may? A. VfDV MINH HQA Bid 2. Cho m¢t be day nu6c hl n h h9p c h u n h �t. NgtJoi ta tha 2 cl;lc sat hl n h l �p phu'Ong th) thay O UOC tran ra 54 1ft Tim C�n h 1 CIJC sat DANG 1: DUNG Ll.IU DO . Bai 3. San tniong Nguyen Tat Tha n h c6 chu vi I a 1 42 m . Neu ta ng Vi d y 1 : Ti m m qt sol biet neu lay so d6 gap len 2 Ian roi. tru di 1 Of duqc bao n h ieu chh2u r¢n g len 015m va g i a m c h i e u d a i di O,S m th1 m a n h dat tha n h chia cho thl avqc o. hl n h vu6ng. Tfnh di�n tlch san .truong. 4 ket q ua Ia 1 Bid 4. An viet mot so bang. � cua so M. N h un g do so suat n e n An -1 4- Bai lam: ! j Thea de bai da vh�t m<)t s 6 ba n g cua so M. B i et hi$U cua so mai va so cO ba ng ta c6: . I 1 50. Tim M. I x 2 - 1 0 I - B it i 5. MC)t c h i ec xe a�p c6 au'O'ng kfn h ba n h trvac Ia 017m va dvong kfnh ba n h sau Ia 0,9m. Neu ban h truac q uay dUQ'c 1 35 vong thl b a n h sa u q uay dli<!C may vong? 56 chia cho 4 Ou'<;fC ke't qua bang 1 0 Ia: 1 0 X 4 = 40 Bai 6 MC)t ngVoi l ai xe tfn h: neu di voi v� n toe 40km/h thl se den h.J c .. ai 1 o auc;1c ket qua bang Ia: 1 1 0 g i o 1 5 p h ut con neu d i Vdi v�n toe SOkm/h th1 s e den l uc 9 g ia 45 s6 tru 40 40 + o = so phut. Tfnh quang au'ong xe da dL 56 can tim Ia: 50 : 2 25 Dap so: 25 Bai 7. Co hai n g a n sach. Tong so sach 2 ngan Ia 1 50 q uyen. Neu = chuyen 5 quyen tu ngan d voi l e n nga n tren th1 so siKh nga n tren DANG 2: DUNG SCIDO £JOAN THANG bang 3_ so siic h ngan duoi. Tl m s6 sach ngan duaL Vi h m hoa � sO B 6i chieu bim 3 d �;� 2: MQt q uay i g bii n qua, b u Oi sa n g ba n Qu'gc cam . u Bai 8. Lan va Hoa lam m¢t c6ng vi�c. La n lam m()t mlnh m at 5 g i a. ! H oa l a m m<)t m1 n h m at 7 gio Hoi hai b�n cu n g lam thl sau bao l a u se . du<;Jc so ca m con l9i sa u kh i ban b u o i sa n g thl con 6 kg . Hoi luc da u quay h ang c6 xong? Bid 9. M 9t n h6m g o m 9 nguoi lam tren m¢t manh dat 30m2 thl rnat bao n hi eu ki:-16-gam ca m ? 60 ph ut. Neu 1 8 nguai l a m tre n m a n h oat 1 5 m 2 thl bao l a u se xon g - B a i liun: c6ng vi�c. Bi et sue l a m moi nguoi nhv n ha u . Ttl lu�n ················�··········..··--·..······-··-····· - Cach 1 : Ta c6S Cfao: Phan 2: B�ti 1 0 M<)t a¢i tV ng uy�n trvong N g u yen Tat Tha n h ai tr6ng c a y iJ ti n h Ha Gia n g .. 56 cam luc aau: tro ng 3 n gay. Ngay 1 d¢i trong -31 tong s6 cay N g ay 2 d¢i tr6ng -� s o cay con I<;1L . 1 1 buoi sang: Ngay 3 tron g it hon ngay 2 Ia 3 0 cay. Tfnh so cay m a a<)i da tro n g . Con IQi sau B a i 1 1 8o9 n du'ong tu H a N 9 i den H a Giang dai 330km. M ¢t 6 t o x uat phat t u Ha .. lgi sau buoi chieu: N(>i luc 6 g i& voi v? n toe 55 km/h . Cung l u c 2 xe taxi va xe t2ii xuat phat tu Ha Giang Con 6kg v&i v� n t6c 65 km/h va 45 km/h . a) Vao l u c m ay g ib thl taxi g� p 6 to? 56cam con lr;�isau khi ban buoi sang Ia: 6 x 4 = 24(kg) b) Vao l uc may g i C:t thl kh o i m g each g i ua 6 to va taxi bang khoa n g each giU'a 6 to va 56cam /uc aau quay hang c6 Ia: 24 : 3 5 40(kg) xe tai ? X � f)dp so: 40kg a ndRise above onese l f A rc h i medes School I 65 g rasp t h e world Aschoo l .ed u .vn
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kh� 2 3 ( ) 56c a m c o n lq�is o u b a n b uoi sang 1 - - 'so'>' cam ban uau.:::t A' = - 5 5 d�t ct6 3 56cam buoi chh�u ban fa: � � = � (socam ban C!au) t ro n g k h o i l � p p hud n g ki m 5 x I 4 20 lo�i c�n h 1 Ocm (Nhu h! n h ve). Sau d6 : b 2 9 1 7 ( "' S ' h o cam" buo1 c 1eu va' b ,-,7 sang a nr Ia:' - so cam ban u a u.A- ,., ) do duqc vao t h u n g tu m qt voi v6'i toe "' • • ,..' uot• r + / r )- - = - 5 20 20 a¢ c hay. 4 lit/phut thl sa u 1 5 phut "--/ __y Hoi chit2u a c _______ 56 cam con IQi so u khi ban b u oi chieu /t]: 1 - i 7 = ]__ (socam ban aa�) th u ng day n ude. ca ua 20 20 th u ng I a baa nhieu cent i m et? ]_ 56cam lucaau quay h ang co la: 6 : = 40 (kg) C a u (0,75 diem) Tren cay & san tnJang N g u ye n Tat Tha n h c6 1 o 20 con c h i m da n g d�u Ci hai ca n h cay. C6 1 con tli ca n h t re n bay x u o n g £Jap so: 40kg . can h dvai va 3 con bay tu canh d vai l en canh tren, kh i ay s6 chim a ca n h tre n ba ng h ai pha n ba so chim 6 can h d voi . Hoi l u c da u can h DANG 3: DUNG BANG d uc1i co bao nhieu con chi m? Vi d �;� 3 : Ba b 9 n A n, Blnh, C h i s u'u tam du<;jc tat ca 1 08 chiec te m . Neu An c h o Bl nh 1 0 Cau 9. (0,75 ait�m) N h a truO'ng t o ch uc h¢ i chq d� g a y q uy u ng h9 "Vl Truong Sa tha n yeu" Lop ve m9t a h va em ba n dau g ia chiec Bl n h c h o C h i 8 ch iec t hl s6 tern cua ba b C? n bang n h a u . H o i m o i b� n s uu tam 6A buc tr n d v&i , i g i a d lf kien I a 280000 do n g . Nguoi thu n hat tra cao hon g i a d y' kh�n duqc bao n h ieu c h i ec tern? l 1 O%,nguoi t h u h a i tra cao h o'n nguoi thu nhat ava ra Ia 1 0°/oJ ngVO'i th u Ba i l a m : ba tra ca o ho'n g i a n g ubi thu h a i dua ra I a 5 °/o va m ua ctuqc b uc tra n h . H o i cuoi c u n g , b uc tranh duqc ba n voi g i a bao nhieu? Ta c6 bang sau: -· ........ ....................- ····· ·········· ······ ······-···-········ ........................_ C a u 1 0 (0,75 diem ) Lop 6A di tu t h i � n -t? i B�n h vi$n H uyet h 9c, Ban to An Blnh Chi .. chuc ca n m ua 200 h <)p sua va 50 goi ba n h . Bh2t ran g m<)t h¢p sua gia ·········-·······--·· ···--------------·- 5000 do n g � m ¢t g6i ba n h gia 2 5000 dong Cua h a n g kh uyen m� i m u a Cu6i cung 36 36 36 . s h9p sua augc t�ng 1 h <)p, m ua 1 o g 6i ba n h dugc t�ng 1 g 6 i . H o i ton g Trude khi 8/nh cho 36 36 + 8 = 44 36 - 8 = 28 so th2 n Ba n to c h uc p h a i tra Iaba a n h i e u ? Truac khi An cho Ill. Tl! lu�n 36 + 1 0 = 46 44 - 7 0 = 34 28 {luc aau) H QC si nh t h ljc h i ¢n yeu ca u q phan b6 tr6ng du6'i moi ca u hoi. --�------ ' Cau 1 1 (2 diem) Tron g so h qc s i n h tha m g ia d lf an c h a m s6c hoa , cay canh f.J k h u o n Gfai thfch bang: .. v i e n t rvon g N g uyen Tat Th a n h � so h9c si n h l op 9 chiem 2525, s6 h 9c sin h l dp 8 Sau khi cho cfi rnoi ngUdi c6 s6 tem Ia: 1 08 : 3 = 36 (con tern) co n chiem 1 3 1 3 , con lqi Ia so hqc s i n h !6'p 7 va lop 6. Biet rang ton g so h Qc s i n h lop 6; 7; 8 tham g ia I a 1 26, so h9c si nh I Cip 6 tham g ia b a n g 3434 so h Q c si n h fop 7. Hay ti m so 56 con tem cua Ch i Ia: 36 - 8 = 28 (con tern) h QC s i n h lop 6 aa tham g ia dl,f a n? 56 con tern crJa An fa: 36 + 7 0 = 46 (co n tem) Cau 1 2. (2 diem) M o i sang N a m cung a n h c h9y be) q ua n h ba h6 N g hia Ta n. Ha i a n h = Ch 9 Y v�n toe h n do i, x u at cu n g m 9t l u cf t li m ¢t 56 con tern cua Blnh Ia: 36 - 1 0 + 8 34 (con tem) e m cu n g c h ieu vai k o g phat c u n g ctie m thl sau 45 p h ut l9 i g�p n h a u . Tfn h v� n toe trun g bl n h c u a N a m . Bh�t ding m9t £Jap s6:A n: 46 con tem; Blnh: 34 tem; Chi: 28 con tem con vong q ua n h b0 ho dai 3 km, Nam C h<?Y ch� m h on anh va neu c h 9Y ng liQ'C c h i eu thl sau 1 0 h Vi H uy va H o a ng c6 m9t s6 bi. Neu H uy c h o H oa n g m <?t so b i du ng bang s6 b i p ut l 9 i g � p n hau? m a H oa n g da n g c6, r6i Hoa ng l � i cho H uy m()t s o br dung bang s 6 b i co n l<?i c u a Huy l u c d6 thl Hoa ng se c o n 3 5 vien bi va H uy c6 30 v i e n b i . H o i l uc da u m o i b�n c6 b ao n h ieu vlen b i ? Rise bo e 1 1 a v o neself A rch i med es School a nd g rasp the world Aschoo Led u .vn
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A RCH I M ED ES SC H OOL Toa n 5 - Quyen 4.1 Bai Jam: flETH I VAO LOP 6 TRlJ<1NG NGUYEN TAT THANH (201 8_- 201 9) 1. Trac nghi�m · Ta c6 bang sau: Khoanh tron chCfcai trtfoc moi aap an aung: Moi cau tra lai dung duqc 0,5eliem Huy Hoang Cau 1 . So li$u thon g ke xep l o� i h 9c h jc cua hqc si n h tnidng N guyen Tat Tha n h Cuoi cung 30 35 trong 4 n a m duqc cho trong bang d ttoi day. B i et ran g h Q c h,fc cua hqc sinh au'qc c h i a · . Tnlac khi Hoang + lam ba l oc;:t i: G ioi, Kha v a Trung bln h . Hoi na m h q c n a o t i I � h<;>c sinh xep- Jo9 i Trung cho 30 : 2 = 1 5 35 1 5 = 50 bl n h cua tnJong I a cao nhat? Tnrac khi Huy cho Xep lo�ti hqc lye 15 + 25 = 40 50 : 2 = 25 Nam hqc (luc aau) Gioi Kha 201 4 - 20 1 5 6918o/o 28,5°/o Giai thich bang: · 2 0 1 5 - 20 1 6 79169i> 1 914°k Tnloc khi Hoang cho, s6 bi cua Huy fa: 30 : 2 1 5 (vien) 20 1 6 - 20 1 7 8314o/o 1 6,2o/o = 20 1 7 - 20 1 8 85,7% 1 3,4°/o Tnlac khi Hoang cho, so bi cua Hoang Ia: 35 + 7 5 = so (vien) B. Nam hQC A. N a m h9c 20 1 4 - 20 1 5 20 1 5 - 20 1 6 Luc dau Hoang co so bi Ia:so : 2 = 25 (vien) c. N a m h9c 201 6 - 201 7 D. Na m hQC 2 0 1 7 - 20 1 8 Cau 2. D9i tln h ng uy�n tntong Ng uyen Tat Thanh l a m tu th i�n t�i m9t tn.ton g h9c Luc aau Huyc6 s6 bi Ia: 15 + 25 = 40 (vien) fJap so: Huy: 40 vien; Hoang: 25 vien cua Ha ke h o9ch/ (J manh cha dai tln h Giang. Theo d¢i se dQn co m ¢t dat h1 n h n h�t B . BAI T�P 220m, r¢ng 1 30m trong khuon vien cua tnJO'n g . fJ Q i d a d Q n duqc co voi di¢n tfch 1 12ha. Hoi d i�n tfch p h a n dat con l9i ch ua dugc dqn co? Bai 3 1 . 11 m m¢t 501 biet l ay so d6 tn1 di 1 1 r6i ch i a cho 7, l ay thuong tim duqc c¢ng A. 1 6L6 ha B. 1 216 h a C . 1 ,66 h a D. 28,6 ha voi 3, dU'Q'c bao n hi e u n h a n voi 8 th1 duqc ket q u a I a 80. Cau 3. H uerng u n g dtf a n JJA o a m cho h <;> c s i n h v u n g kh6 khan (J tinh H a Giang'/ cua tniong Nguyen Tat Tha n h/ l o p 6A p ha n c6ng cac b9 n t V l a m bt1a s a n g de c a l o p cung a n , tiet ki�m t i e n de th ljc h i�n d lf a n. Den l uqt nh6 m c u a b g n A n l a m ba n h m l k�p1 An cu n g nh6m tr9 n th!t xay voi khoai tay n g hi e n voi ti I � 3 : 2 de l a m 4 kg nhan banh . H o i nh6m cua A n da dung bao nh ieu ki-16-gam th jt xay ? A . 214 kg B. 2,5 kg C. 1 16 kg D. 1 15 kg Ca u 4.. Viet l ie n tit�p ca u /'TRVONG NGUYEN TAT THANH" 20 Ia n . Hoi am E cuoi c u n g dun g (J v! t rf th u may? A. 400 8. 325 C. 3 50 0. 3 9 1 II. Tra lai ngan Viet cla p so cua bai toan vao 6 de trong. Bfd 32. Nam n g hi ra m()t so. Lay s6 d6 c¢ng voi 0121 dugc bao n hi<�u tru di 0, 5 � l ay Cau 5. (0, 5 di em) Xe 6 to chd doan tu thi�n cua tniong Ng uyen Tat ket q ua nhan voi 2; du'9'C bao nh ieu chia cho 0, 1 thl dU'qc 1 2. Nam da n g hl ra so nao? Thanh roi Ha N9i l uc 6 g iO' sa ng va di len tin h Ha G i a ng voi v�n toe tru ng b1 n h Ia 5 5 km/h . Cung l u c <.16, m¢t xe tai di tu Ha Giang ve Ha N¢i tren cu ng tuyen avong va h a i xe g�p n h a u luc 9 gia. Hoi v� n toe trung Ibln h cua xe ta i? Biet q u a n g duang tu Ha N¢i toi Ha Giang I a 3 00 km ? cau 6 . (0,5 di�rn) Tron g dgt: aa n g kf tham g ia c.k ca u l <,� c b 9 (CLB) 0 i truong Ng uyen Tat Tha n h, moi hQc si n h dvqc da ng kf th a m g ia tu 1 I1 den 2 CLB. C6 ton g so 30 h9c si n h l op 6 aa n g kf vao C LB Ph6ng vien va li�LB Khoa h Qc, trong d6 c6 1 5 h?�c s}nh da�g kl C LB ��6ng vien, 20 h9c _ s a n h da�ng kt, CLB Kh. oa h9c. Ho1 co 1t, n h at bao n h teu h9c s t n h. l dp 6 da n g kJ tham g ia ca hai CLB? Rise a bove oneseff Arch i medes S chool I 63 a n d g rasp the worl d Aschoo l.ed u .vn
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m 1 l 2 4 s6 ba n g � ra vdi 1 3 so 60°/o so so ba n g ba o n h h�u s6 A. 60o/o B. 80o/o ?Oo/o D. 90°/o C6 bao n hieu so c6 2 c h u so ma s6 d6 g ap 4 1a n to n g 2 c h u so cua n6? 8. 3 C. 4 D. S N a m nay t u o i bo g a p 8 la n tuoi be A n , tuoi m� g a p 7 la n t u o i be An va bo hdn m� 4 tuo i H oi sang nam be An bao n h i eu t u o i ? . A. 3 B 4 C. S 0. 6 . C h o hl n h ve. Tfn h tl s6 d i � n tfch 2 tam giac B DF va AEF. Mot. n g uoi ban d ua, lan thu nhat ban � so d ua . U1 n thu hai b a n _! s6 dua A 4 2 con l <;l i thl con 1 50 q ua d ua . Hoi nguO'i d6 man g ban bao nhieu q u a dva? B D c A. 2 B. 1 ,5 C. 3 D. 1 Bai N g uoi th u n hat l a m xong c6 n g vi�c t ro n g 5 g io, n g lfai t h u hai l a m xo n g cong vi�c trong 4 gio. Hoi ca 2 ng u'oi c u n g lam mat bao l a u ? A. 2 0 g i a B. 9 g i o !_ ia c. g o. 20 g io � � 20 9 35.. M9t h a n g ban th u n hat ba n so ngay thu hai b a n so m¢t 1 Om, B a i cua g �o, n g a y g�o; Bai 6. Ng lfoi ta xay be n uoc, c h i e u da i 1 5 m , c h ie u r{}n g m ¢t kh u c6 a() sa u O,Bml m 9t kh u c6 d9 sa u 1 m , h a i k h u c6 d i � n t fc h m�t nuac b a n g n hau. Hoi m u on g�o co n l9 i 1 6kg . Ngay th u ba cua h a ng ba n 0kg n ua t hl vua het s6 990. Hoi !Lie va 4 m?t n uoc each m �t be 1 Ocm t hl p hai xa vao bao n h ieu m et kh6i n uoc, biet be ch ua c6 n uoc da u cU'a h a n g d6 c6 bao n h ieu ki- 1 6-g a m g �o? A. 90m3 B . 1 20m3 C. 1 3 5m3 D. 1 05 m3 Phan 2: Tt! lu�n Bai 7. C6 3 can d a u . Sau khi can I cho can I I 211 ca n II cho ca n I l l 3/ thl s o dau ca n I ba n g 3_ ton g s o d a u v a c a n I I c 6 s 6 d a u bang 75o/o s o da u ca n I l l . H o i l u c da u m o i can c 6 b a o 9 n hieu Ht dau biet sa u kh i ch uye n thl can I l l n hi e u han ca n I Ia 8/. Quang duong AB dai 60k m . C u ng l uc c6 xe di tu A va tli B khO'i h a n h. Sa u 23._ 9 g i a thl c h u n g g� p n hau N eu v�n toe xe di tu B ta ng them 3 km/h thl h a i xe se g � p . nhau a c h fn h giua q uang duO'ng A B . Tfn h v � n toe m o i x e l uc da u . 1 19 Rise above oneself A rc h i med es S c h oo l a nd g ra s p the wo rl d Asch o o l .edu .vn
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ARCHI M EDES SCHOOL Toan s - Quyen 4. 1 Bai 36. An dQc m(>t quyen truy�n trong ngay. Ngay dau An d9c ch.Jqc �-so trang va BAI 4. MOT s6 f>E TH I ba 1 6 trang. Ngay th U hai An dqc til�p 130 s6 trang cOn l�i va 20 trang, n gily thU ba An dqc f>ETHI VAo LOP 6 THCS cAu GIAY (20 1 9 - 2020) ! 9 ngay Phan 1 : Trac nghi�m so trang con l i sau hai va 30 trang cuoi. Hoi quyen truy�n d6 co baq nhieu 1 34247 1 34267 Biti 1 . Ti m so tlf nh ien X, biet: < 1 34, 2x7 < trang ? 1 000 1 000 Bai 2. Tim so thu 7 cua day 3; 5; 8; 1 3; 2 1 ; . . . Biti 3 . Tfn h gi a trj biE�u thuc 1 01 x 34 + 1 0, 2 x 1 30 - 11 0l x 2700 I Bai 4. Tr m chu so t�n cung cua day sau 1 1 1 3 1 5 1 7 1 9 X X X X X ••• X 20 1 9 B il i 5 . Nam c6 m(>t s6 b t Biet neu xep moi h¢p 5 vh�n thl co n du 3 vien. Neu xep moi ' h<) p 2 h o�c 9 vh�n thl du. Hoi so bi cua Nam bh�t Nam c6 n hieu han 1 1 o vien va ft hon 250 vh�n. Bai 37.Thai Thi¢n, ChVdng c6 tat ca 3 6 q u a bong ba n. Neu Chu'dng cho Tha i 6 qua Bid 6 . Cach day 4 nam ton g so tuo i 2 c h j em I a 28 tuoi H i�n nay tuoi , . . . roi Thai cho Th i�n 6 q ua va Thi$n cho Chuang 4 qua thl so bong ba n cua moi b�n em bang 4 tuoi chi.. Tfnh tuoi em h h� n n ay. bang nhau. Hoi l uc dau moi b� n c6 bao nhh?u qua bong? 5 . Bai 7. M<)t m a n h dat hlnh chu n h�t c6 d i�n tlch Ia 2020m2• Neu ta ng chieu dai len 5 0°/o v a giam chieu n?n g di 20o/o thl d i�n tich moi Ia bao n h ie u hec-ta? Ba i 8 . Cho m¢t so bong xan h va va n g . So bong vang bang � bong xanh. Neu them 6 bo n g vang thl bo ng vang ba ng � bong xanh. Tfnh . . 9 so bon g xan h . Bai 38. Ba b�n Kien, Hoa, Bln h co tat ca 24 q uyen va. Neu Kie n c h o H oa m{>t s6 vi!J s6 va ella H oa , roi Hoa ch_o l9i Bl nh m¢t s 6 vo so va cua B1n h, roi Bl n h Phan 2 : T\1' l u�n b a n g b a n g l9i cho Kien m¢t s6 va bang so vo cua KH�n thl ba b9 n deu c6 s6 vo ban g nhau. Hoi l uc 1 . N a m tu A den B v�n toe 40km/h. -� B a i d tj d!nh di voi f)j qua ng du'an g AB th1 Nam dau moi b�n c6 baa nhh?u quyen vo? 2 nghi 1 5 ph ut. Be den B du ng g io thl N a m phai di vai v� n t6c s okm/h . Tfn h quang avan9 AB. Bai 2 . Cho hl nh tam giac A BC. Lay M tren AB va N tren AC sao cho AM = B M va NC x 2 = NA. a) Tfn h ti so d i¢n tfch ANM va BMNC. b} Cho M N cat BC d D . So san h BC voi C D. a n d g ra spRise a b ove oneselfthe worl d Archi mAschooLedu.vnedes Sc. hool I 6 1 .
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x e 8 1 2 1 B A 3 xe may n g uO'i g � p r6i do _!_ so d b1 nh t h u h a i sa n g m o i 5 1 2 Ht. so 1 ft n uac co t ro n g moi bln h aa u . B a i 1 20. Luc 6 g i a m9t nguO'i xuat p h at di tu A den B v6'i v�n t6c 40km/g i 0', sa u 4 5 p h ut m<?t n g uai khac di tu B ve A voi v� n t o e SOkm/g io. Biet h Q g � p nh au l uc 9 g io 45 B a i 40. Bon b9 n Ttf, H a o, Vi�t, Nam cu n g chai tro chai ch ia b i n h v sa u : p h ut . Tinh d9 d ai qua n g duong A B. Dau ti en, T lf c h ia c h o ba b9 n co n IC;li s o b i gap d6i s 6 bi c u a m oi b9 n hi�n c6. Tiep d6, H a o cu n g c h i a cho ba b9n con l�i s6 bi gap d6i so bi cu a moi b � n h i � n c6 . S a u d6 b�n Vi�t ro i b� n Nam c u ng c h i a n h u v�y. Cu6i cung moi b9 n de u c o 8 1 vien b i . H o i t ruce khi c ho'i moi b <? n c6 bao n h ieu vien bi ? Bid 1 �A9t ca n o di xuoi dong ttt A den B voi v�n toe 50km/gi 0' f)i ng u'qc dong t u • . B den A voi v� n toe 40km/g i a. B i et ton g th ai g ia n ca d i t a n ve I a 2,7 g io. T f n h d ¢ d a i q ua ng auong A B. --·--···---------·------------------ a n d g ra s p the wo rldRise a bove onese lf A rchimed e s S c h o o l I Asc hoo l .e d u .vn
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ARCH I M EDES SCHOOL Toa n s - Quyen 4. 1 II. ON T�P VE TRUNG BlNH CQNG XI. ON T�P VE CHUYEN f>QNG A LY THUYET Bai 1 1 6. M{>t nguoi di xe may tvTha i Bln h luc 6 gio 45 phut de len Ha NQL Sau kh i di .. c¢ng c�c OVQC 1 gio 1 5 phut VOi V� n toe 50km/gid1 nguai do nghi 30 phut roi l�i tiep t\;JC di VOi • Trung bl n h = tong so : so cac so h � n g . v�n toe 45 km/g i o. N g u'ai d6 den Ha N Q i I U c 9 gio 20 ph (Jt. • Trung bl nh c<}ng cua day so each deu = (so aau + s6 cuoi) : 2 a) Tfn h quang duong tU' Thai Bin h len Ha N9L Neu so A h ctn TBC cua A va n so da biet khac (a,, a2, a3, an) Ia x dctn vj thl TBC cua • . . ·r. b) Neu I de dau nguoi d6·ai voi v�n toe 30km/gi o va sau khi nghi l�i di voi v�n toe A va n so a , , a2, a3, . . ., an Ia (a , + a2 + a3 + . . . + an + x) : n . 40knVgia thl den Ha N(>i l uc may g i o? • Neu s o A b e hdn TBC c u a A va n s o da biet khac (a, , a2, a3, . . ., an) Ia x don v! thl TBC cua A va n so a1, a2, a3/ , a n Ia (a1 + a2 + a3 + + an - x) : n. . . . . . . B. Vf Dl} MINH HQA Vi d� 1 : An co 1 8 vien bi1 B1nh e6 1 6 vh�n bi, Chi e6 so vh�n bi nhieu hon tru n g bl n h c¢ng s 6 bi cua b a b�u1 la 2 vh�n. Hoi Chi c 6 b a o nhieu vh�n bi? Bai lam Tru ng blnh moi b9 n c6 so vien bi Ia: (1 8 + 1 6 + 2) : 2 1 8 (vien) Bai = 1 1 7 Luc gio b9n Hung ai tu A den B voi v�n toe 1 5km/g i o, m ¢t g io b� n Tha .. 7 sa u nh Chi c6 so vien bi Ia: duoi theo voi v�n toe 20km/g io. Hoi den may g io thl b�n Thanh duoi kjp b�n Hung? 1 8 + 2 20 (vien) = f)ap �6: 20 vien. Vi dl} 2: X e thu nhat chC1 au'qc 1 20 tan ha ng, x e thu hai chet duqc 78 tan h a n g . X e thu ba chb ol1Q'c it hon trung bl n h c(>ng eua ba xe Ia 1 6 tan h a n g . Hoi x e thu ba ch6' duqc bao-nhieu tan hang ? Bai l a m Biti 1 1 8. Luc 1 2 g io tru'a, m(>t o to xuat p h at tu diem A v6'i v�n toe 60km/gib va d l,J' Tru ng bln h m o i xe c h d duqc s o tan ha ng I a : di n h den 8 luc 3 g i o 30 phut ch ieu. Cung luc d61 tU' ctiem C tren duCing t u A den B va each A 40km, m(>t ngu'oi di xe may vai v�n toe 45 km/giC1 ve B. Hoi l u c may gio 6 to ( 1 20 + 78 - 1 6) : 2 = 9 1 (tan) nguOi auoi ki p di xe may va dja diem g�p nha u each A bao n hieu? Xe thu ba chCI duqc so tan hang Ia: 91 - 1 6 = 75 (tan) 9a p so: 75 tan ha ng. 1 ' 2 2 a n dRise a boveg rasp the worldoneself Arch imedesAsch oo1 .ed u .vnSc.h oo. . I 59
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